Schematic representation of the type of hydrolysis of amidе and carboxylic acid derivatives of nitrile glycosides around a physiologically active cancer and healthy cell

article - DOI: 10.2174/1871520620999201103201008
monograph - DOI: 10.5281/zenodo.7295357 | ISBN: 978-619-91534-4-4
ATLAS - presentation of the finale information in the most applied and convenient form of application - DOI: 10.5281/zenodo.8009390 | ISBN: 978-619-91534-5-1

...The figure present two physiologically active cells: healthy (III.) with pH=7.2 and cancer (V.) with pH=7.4. They are found in a volume of blood (I.) with pH=7.4. Around each cell has an associated volume of liquid (VI.) With specific ionic activity and hence different acidity. For a healthy cell, pH=7.4 and for cancer pH=6.5. Based on the data of it.3, it follows that in a healthy cell, all three hydration forms HF(A;B;C) will be in significant concentration both in the blood (I.) and in the closed volume (II.) around it. In the volume around the cancer cell, the hydrolytic equilibrium is shifted in the HF direction (B). In this form, the molecule loses its activity in an environment of excess protons, i.e. behaves like a "regular carbohydrate".

Based on the fact that the cancer cell feeds primarily on carbohydrates, it is likely that the organisms have adapted to receive food containing nitrile glycosides and/or their modified forms to counteract "external" biological effects. Cancers, for their part, have evolved to the extent that they create conditions around their cells that eliminate the active apoptotic forms. This is far more appropriate for them than changing their entire enzyme regulation to counteract it. In this way, it protects itself and the gene set and develops according to its instructions.

Therefore, the hydration balance of HF(A,B) in the blood, the medium around the cancer cell shifts it in the direction of HF(B). Parallel to this hydrolysis, the carboxylic acid, i.e. from BF(C) to HF(C). It is not sensitive to this change in acidity and the equilibrium is shifted towards the product. This concludes that the concentration of HF(C) is approximately the same in (I) and (IV.) in healthy and cancer cells. This form also could hardly pass through the cell membrane in considerable concentration....